JEE Main 2021 — Electromagnetic Induction Question with Solution
From: JEE Main 2021 (Online) 24th February Evening Shift
Question
Figure shows a circuit that contains four identical resistors with resistance R = 2.0, two identical inductors with inductance L = 2.0 mH and an ideal battery with emf E = 9V. The current 'i' just after the switch 'S' is closed will be :
This question includes a diagram. The text above accompanies the figure.
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Show full solutionCorrect option: D
Correct answer
D2.25 A
Step-by-step explanation
Given, resistance, R = 2,
Inductance, L = 2 mH,
emf, E = 9 V
and i be the current.
At t = 0 when switch is closed, inductors behave as open circuit.
Effective circuit will be
By using Ohm's law, V = i Req
i = V/Req
where, Req is equivalent resistance of series resistors,
i.e., Req = R + R = 2R = 2 2 = 4
A
Inductance, L = 2 mH,
emf, E = 9 V
and i be the current.
At t = 0 when switch is closed, inductors behave as open circuit.
Effective circuit will be
By using Ohm's law, V = i Req
i = V/Req
where, Req is equivalent resistance of series resistors,
i.e., Req = R + R = 2R = 2 2 = 4
A
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