JEE Main 2021 — Electromagnetic Induction Question with Solution
From: JEE Main 2021 (Online) 26th February Evening Shift
Question
An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 104 Wb/m2 and the angle of dip is 60. The emf induced between the tips of the plane wings will be __________.
Choose an option
Show full solutionCorrect option: D
Correct answer
D108.25 mV
Step-by-step explanation
ind = (Bv) LV and Bv = BTotal sin60o
ind = (2.5 104)(sin 60o) 10 180
= 108.25 mV
ind = (2.5 104)(sin 60o) 10 180
= 108.25 mV
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