JEE Main 2021 — Electromagnetic Induction Question with Solution
From: JEE Main 2021 (Online) 16th March Evening Shift
Question
The magnetic field in a region is given by . A square loop of side d is placed with its edges along the x and y axes. The loop is moved with a constant velocity = v0. The emf induced in the loop is :


This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation

We know, Emf = Blv
where B, l and v are mutually perpendicular to each other. If any two are not perpendicular to each other then Emf = 0.
Here for part AB and DC, length l and velocity v is parallel to each other so, Emf by AB and DC is zero.
Given
At x = 0,
For part AD, Emf = 0
In BC part,
x = d
And Emf for BC part,
Here B, v, d are mutually perpendicular to each other.
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