JEE Main 2019 — Electromagnetic Waves Question with Solution
From: JEE Main 2019 (Online) 10th January Morning Slot
Question
If the magnetic field of a plane electromagnetic wave is given by (the speed of light = 3 × 108 B = 100 × 10–6
sin then the maximum electric field associated with it is -
Choose an option
Show full solutionCorrect option: D
Correct answer
D3 104 N/C
Step-by-step explanation
E0 = B0 C
= 100 106 3 108
= 3 104 N/C
correct answer is 3 104 N/C
= 100 106 3 108
= 3 104 N/C
correct answer is 3 104 N/C
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This is a previous-year question from JEE Main 2019, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.