JEE Main 2023PhysicsElectromagnetic WavesDisplacement Current And Properties Of Em WaveseasyMCQ

JEE Main 2023Electromagnetic Waves Question with Solution

From: JEE Main 2023 (Online) 10th April Evening Shift

Question

The amplitude of magnetic field in an electromagnetic wave propagating along y-axis is . The maximum value of electric field in the electromagnetic wave is

Choose an option

Show full solutionCorrect option: C
Correct answer
C

Step-by-step explanation

In an electromagnetic wave, the maximum value of the electric field E is related to the maximum value of the magnetic field B by the equation



where c is the speed of light in a vacuum, which is approximately .

Given that the amplitude of the magnetic field B is , we can substitute these values into the equation to find the maximum value of the electric field:



Therefore, 180 V/m is the correct answer.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.