JEE Main 2026 — Electromagnetic Waves Question with Solution
JEE Main 2026 (06 April Shift 1)
Question
A point light source emits E.M. waves in free space. A detector, placed at a distance of m, measures the intensity as . The detector is now shifted to another location on the same spherical surface ensuring the angle between original location and new location as . The measured intensity at new location will be _______.
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
For a point light source, the intensity of electromagnetic waves at a distance is given by , where is the power of the source.
Since the detector is moved to a new location on the same spherical surface, the distance from the source remains .
The emission from a point source is isotropic, meaning the intensity depends only on the radial distance from the source and is independent of the angular position.
Therefore, the intensity at the new location remains unchanged, which is .
Answer:
Since the detector is moved to a new location on the same spherical surface, the distance from the source remains .
The emission from a point source is isotropic, meaning the intensity depends only on the radial distance from the source and is independent of the angular position.
Therefore, the intensity at the new location remains unchanged, which is .
Answer:
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2026, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.