JEE Main 2019 — Electromagnetic Waves Question with Solution
From: JEE Main 2019 (Online) 9th April Evening Slot
Question
50 W/m2 energy density of sunlight is normally
incident on the surface of a solar panel. Some
part of incident energy (25%) is reflected from
the surface and the rest is absorbed. The force
exerted on 1m2 surface area will be close to
(c = 3 × 108 m/s) :-
Choose an option
Show full solutionCorrect option: A
Correct answer
A20 × 10–8 N
Step-by-step explanation
Radiation pressure for 100% reflection =
Radiation pressure for 0% reflection =
Hence, in given case, radiation pressure
=
Force = P × (Area) = 20.83 × 10–8 N
Radiation pressure for 0% reflection =
Hence, in given case, radiation pressure
=
Force = P × (Area) = 20.83 × 10–8 N
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This is a previous-year question from JEE Main 2019, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.