JEE Main 2020 — Electromagnetic Waves Question with Solution
From: JEE Main 2020 (Online) 3rd September Morning Slot
Question
The magnetic field of a plane electromagnetic wave is
T
where c = 3 108 ms–1 is the speed of light. The corresponding electric field is :
T
where c = 3 108 ms–1 is the speed of light. The corresponding electric field is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B V/m
Step-by-step explanation
Given, T
E0 = CB0
= 3 × 108 × 3 × 10–8 = 9 V/m
We know,
And here
So, V/m
E0 = CB0
= 3 × 108 × 3 × 10–8 = 9 V/m
We know,
And here
So, V/m
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This is a previous-year question from JEE Main 2020, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.