JEE Main 2026 — Electrostatics Question with Solution

Six point charges equally spaced 60° apart on a circle of radius R, with alternating arrangement creating a dipole-like configuration.
Each charge creates an electric field at the center of magnitude $E_0=\frac{Q}{4\pi {\epsilon }_0{R}^2}$ pointing radially (outward for +Q, inward for -Q).
By vector addition of field contributions from all six charges with proper angle consideration:
The charges at specific positions create a net field with components that depend on their arrangement.
For the given symmetric configuration, the net electric field is: $\vec{E}=\frac{Q}{4\pi {\epsilon }_0{R}^2}(\sqrt{3}\hat{i}-\hat{j})$
This corresponds to magnitude $2E_0$ at angle of $-30°$ from the positive x-axis.