JEE Main 2019 — Electrostatics Question with Solution

Charges –q and +q located at A and B, respectively, constitude an electric dipole. Distance AB = 2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP = y and y >> 2a. The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P' such that OP' = $$\left(\frac{y}{3}\right)$$, the force on Q will be close to - $$\left(\frac{y}{3}>>2a\right)$$