JEE Main 2021 — Electrostatics Question with Solution
From: JEE Main 2021 (Online) 25th February Morning Shift
Question
512 identical drops of mercury are charged to a potential of 2V each. The drops are joined to form a single drop. The potential of this drop is ________ V.
Enter your answer
Show full solutionCorrect answer: 512
Correct answer
512
Step-by-step explanation
Let charge on each drop = q
radius = r
radius of bigger
radius = r
radius of bigger
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electrostatics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.