JEE Main 2025 — Electrostatics Question with Solution

Therefore, the relationship between charge density and ROC at different points can be expressed as:

$\sigma \propto \frac{1}{\mathrm{ROC}}$

From this, the relationship between the charge densities at the specified points becomes clear:

$(\mathrm{ROC}{)}_1<(\mathrm{ROC}{)}_3<(\mathrm{ROC}{)}_2=(\mathrm{ROC}{)}_4$

This implies:

${\sigma }_1>{\sigma }_3>{\sigma }_2={\sigma }_4$

Thus, the charge density is greatest at the point with the smallest ROC and decreases as the ROC increases, keeping in mind that ${\sigma }_2$ and ${\sigma }_4$ have equal ROC, hence equal charge densities.