JEE Main 2019 — Electrostatics Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
In free space, a particle A of charge 1C is held fixed at a point P. Another particle B of the same charge and
mass 4g is kept at a distance of 1 mm from P. If B is released, then its velocity at a distance of 9 mm from P
is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B6.32 104 m/s
Step-by-step explanation
qA = 1 c ; qB = 1 c, mB = 4 × 10–9 kg, rAB = 10–3 m
V = = 6.32 104 m/s
V = = 6.32 104 m/s
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This is a previous-year question from JEE Main 2019, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.