JEE Main 2020 — Electrostatics Question with Solution
From: JEE Main 2020 (Online) 9th January Evening Slot
Question
An electric field N/C
passes through the box shown in figure. The
flux of the electric field through surfaces ABCD
and BCGF are marked as and
respectively. The difference between is (in Nm2/C) _______.
passes through the box shown in figure. The
flux of the electric field through surfaces ABCD
and BCGF are marked as and
respectively. The difference between is (in Nm2/C) _______.
This question includes a diagram. The text above accompanies the figure.
Enter your answer
Show full solutionCorrect answer: -48
Correct answer
-48
Step-by-step explanation
Flux via ABCD
I = = 0
Flux via EFGH
II =
= [].4
= 16x = 16 3 = 48
= 0 - 48 = -48 Nm2/C
I = = 0
Flux via EFGH
II =
= [].4
= 16x = 16 3 = 48
= 0 - 48 = -48 Nm2/C
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