JEE Main 2026 — Experimental Physics Question with Solution
JEE Main 2026 (24 January Shift 2)
Question
In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division , then the least count of the vernier callipers is mm.
Choose an option
Show full solutionCorrect option: C
Correct answer
C0.002
Step-by-step explanation
Given: 50 vernier divisions = 48 main divisions and 1 main division = 0.05 mm
50 vernier divisions = 48 × 0.05 = 2.4 mm
1 vernier division = 2.4/50 = 0.048 mm
Least count = 1 main division - 1 vernier division = 0.05 - 0.048 = 0.002 mm
50 vernier divisions = 48 × 0.05 = 2.4 mm
1 vernier division = 2.4/50 = 0.048 mm
Least count = 1 main division - 1 vernier division = 0.05 - 0.048 = 0.002 mm
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This is a previous-year question from JEE Main 2026, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.