JEE Main 2021PhysicsGravitationAcceleration Due To Gravity And Its VariationmediumMCQ

JEE Main 2021Gravitation Question with Solution

From: JEE Main 2021 (Online) 20th July Morning Shift

Question

A person whose mass is 100 kg travels from Earth to Mars in a spaceship. Neglect all other objects in sky and take acceleration due to gravity on the surface of the Earth and Mars as 10 m/s2 and 4 m/s2 respectively. Identify from the below figures, the curve that fits best for the weight of the passenger as a function of time.

JEE Main 2021 (Online) 20th July Morning Shift Physics - Gravitation Question 118 English

This question includes a diagram. The text above accompanies the figure.

Choose an option

Show full solutionCorrect option: B
Correct answer
B(c)

Step-by-step explanation

Given,

Acceleration due to gravity on Earth, gE = 10 m/s2

and acceleration due to gravity on Mars, gM = 4 m/s2

We know that, gE (at height h) =

Weight at Earth, mgE = 100 10 = 1000 N

As the spaceship moves far away from Earth, the value of gE decreases to zero at a point where gE + gM = 0 and hence weight will also be zero.

This point is called neutral point and is shown by graph (c) in the given figure.

Then, gE increases 4ms2 at Mars surface and weight becomes 400N which is also exhibited by graph (c).

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About this question

This is a previous-year question from JEE Main 2021, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.