JEE Main 2023PhysicsGravitationEasyMCQ

JEE Main 2023 — Gravitation Question with Solution

JEE Main 2023 (29 Jan Shift 1)

Question

Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational attraction. The speed of each particle will be :

Choose an option

Show full solutionCorrect option: D
Correct answer
DGm4r

Step-by-step explanation

Let speed of both the particles be v.

Then, gravitational force between the particles will provide the required centripetal force.

Therefore,

Gmm2r2=mv2r

⇒v=Gm4r

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About this question

This is a previous-year question from JEE Main 2023, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.