JEE Main 2020PhysicsGravitationMediumMCQ

JEE Main 2020 — Gravitation Question with Solution

JEE Main 2020 (05 Sep Shift 1)

Question

The value of the acceleration due to gravity is g1 at a height h=R2 (R= radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface the earth. The ratio dR equals:

Choose an option

Show full solutionCorrect option: B
Correct answer
B59

Step-by-step explanation

Given that

gn=gd

GM(R+h)2=GMR3(R-d)

GM(R+R/2)2=GMR3(R-d)

4GM9R2=GMR21-dR

49=1-dR

dR=1-49=59

d=59R

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About this question

This is a previous-year question from JEE Main 2020, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.