JEE Main 2023PhysicsGravitationEasyMCQ

JEE Main 2023 — Gravitation Question with Solution

JEE Main 2023 (13 Apr Shift 1)

Question

A planet having mass 9 Me and radius 4Re, where Me and Re are mass and radius of earth respectively, has escape velocity in km s-1 given by: (Given escape velocity on earth Ve=11.2×103 m s-1)

Choose an option

Show full solutionCorrect option: B
Correct answer
B16.8

Step-by-step explanation

The escape velocity on earth is given by Ve =2GMeRe

Escape velocity for the planet is  

V'esc=2G(9Me)4Re   ...(i)

The escape velocity of earth is Ve=11.2×103 m s-1

From equation (i)

V'esc=942GMeRe=32×11.2×103 m s-1⇒V'esc=16.8 km s-1

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About this question

This is a previous-year question from JEE Main 2023, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.