JEE Main 2022PhysicsGravitationEasyMCQ

JEE Main 2022Gravitation Question with Solution

JEE Main 2022 (27 Jun Shift 2)

Question

Four spheres each of mass m form a square of side d (as shown in figure). A fifth sphere of mass M is situated at the centre of square. The total gravitational potential energy of the system is

Choose an option

Show full solutionCorrect option: A
Correct answer
A-Gmd4+2m+42M

Step-by-step explanation

The total gravitational potential energy of the system is 

Usystem=U12+U23+U34+U41+U13+U24+U15+U25+U35+U45

=-4Gmmd-2Gmmd2-42GMmd

=-4+2Gm2d-42GMmd

=-Gmd4+2m+42M

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Gravitation chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.