JEE Main 2016PhysicsGravitationHardMCQ

JEE Main 2016 — Gravitation Question with Solution

JEE Main 2016 (09 Apr Online)

Question

The figure shows an elliptical path ABCD of a planet around the sun S such that the area of triangle CSA is 14 the area of the ellipse. (see figure) with DB as the major axis, and CA as the minor axis. If t1 is the time taken for the planet to go over path ABC and t2 for path taken over CDA then:

Choose an option

Show full solutionCorrect option: C
Correct answer
Ct1=3t2

Step-by-step explanation

Using Kepler's law,

Area ABCDA=x.

Area SABCS=x4+x2=3x4.

Area SADCS=x2-x4=x4.

Since Arial velocity remains constant. Therefore, area swept will be proportional to time.


3x4x4=t1t2
⇒t1=3t2

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About this question

This is a previous-year question from JEE Main 2016, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.