JEE Main 2026 — Kinetic Theory of Gases Question with Solution
JEE Main 2026 (28 January Shift 2)
Question
The mean free path of a molecule of diameter at the temperature and pressure , is given as m.
(Given ).
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Mean free path is calculated using
Given: m, K, Pa, J/K
Numerator:
Denominator:
m = m
Given: m, K, Pa, J/K
Numerator:
Denominator:
m = m
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This is a previous-year question from JEE Main 2026, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.