JEE Main 2018 — Laws Of Motion Question with Solution
From: JEE Main 2018 (Offline)
Question
Two masses m1 = 5 kg and m2 = 10 kg, connected by an inextensible
string over a frictionless pulley, are moving as shown in the figure. The
coefficient of friction of horizontal surface is 0.15. The minimum
weight m that should be put on top of m2 to stop the motion is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: C
Correct answer
C27.3 kg
Step-by-step explanation
Moving block will stop when the friction force between m2 and surface is tension force.
So condition for stopping the moving block,
When m is minimum then,
= 23.33 kg
So if m 23.33 kg then the motion will stop. From option the minimum possible m is 27.3 kg.
So condition for stopping the moving block,
When m is minimum then,
= 23.33 kg
So if m 23.33 kg then the motion will stop. From option the minimum possible m is 27.3 kg.
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This is a previous-year question from JEE Main 2018, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.