JEE Main 2021 — Laws Of Motion Question with Solution
From: JEE Main 2021 (Online) 16th March Evening Shift
Question
A body of mass 2 kg moves under a force of N. It starts from rest and was at the origin initially. After 4s, its new coordinates are (8, b, 20). The value of b is _____________. (Round off to the Nearest Integer)
Enter your answer
Show full solutionCorrect answer: 12
Correct answer
12
Step-by-step explanation
time = 4 sec
As body start from rest therefore
position vector initially &
u (initial velocity) = 0
given,
Now, from second equation of motion
The value of b = 12
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Laws Of Motion chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.