JEE Main 2018 — Laws Of Motion Question with Solution
From: JEE Main 2018 (Online) 15th April Evening Slot
Question
A body of mass 2 kg slides down with an acceleration of 3 m/s2 on a rough inclined plane having a slope of . The external force required to take the same body up the plane with the same acceleration will be : (g = 10 m/s2)
Choose an option
Show full solutionCorrect option: B
Correct answer
B20 N
Step-by-step explanation
When mass slide down then,
Mgsin Mg cos = Ma
a = g(sin30o cos30o)
When mass pushed upward with force F,
F Mgsin Mgcos = Ma
F = Mg(sin30o + cos 30o) + Mg(sin30o cos30o)
F = 2Mg sin30o
= 2 2 10
= 20 N
Mgsin Mg cos = Ma
a = g(sin30o cos30o)
When mass pushed upward with force F,
F Mgsin Mgcos = Ma
F = Mg(sin30o + cos 30o) + Mg(sin30o cos30o)
F = 2Mg sin30o
= 2 2 10
= 20 N
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This is a previous-year question from JEE Main 2018, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.