JEE Main 2002 — Laws Of Motion Question with Solution
From: AIEEE 2002
Question
Three identical blocks of masses are drawn by a force with an acceleration of on a frictionless surface, then what is the tension (in ) in the string between the blocks and ?
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Assume tension between block A and B is T1 and block B and C is T2. Acceleration a = 0.6 m/s2.
For block A :
F - T1 = ma
For block B :
T1 - T2 = ma
By adding both those equation we get,
F - T2 = 2ma
T2 = F - 2ma
T2 = 10.2 - 220.6 = 10.2 - 2.4 = 7.8 N
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This is a previous-year question from JEE Main 2002, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.