JEE Main 2021 — Laws Of Motion Question with Solution

As shown in the figure, a block of mass $$\sqrt{3}$$ kg is kept on a horizontal rough surface of coefficient of friction $$\frac{1}{3\sqrt{3}}$$. The critical force to be applied on the vertical surface as shown at an angle 60$${}^{\circ }$$ with horizontal such that it does not move, will be 3x. The value of x will be _________.

[g = 10 m/s²; sin60$${}^{\circ }$$ = $$\frac{\sqrt{3}}{2}$$; cos60$${}^{\circ }$$ = $$\frac{1}{2}$$]