JEE Main 2019 — Laws Of Motion Question with Solution
From: JEE Main 2019 (Online) 12th April Evening Slot
Question
A spring whose unstretched length is l has a force constant k. The spring is cut into two pieces of unstretched
lengths l1 and l2 where, l1 = nl2 and n is an integer. The ratio k1/k2 of the corresponding force constant, k1 and
k2 will be :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
For a spring, k = constant.
k1 = k2
= =
k1 = k2
= =
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This is a previous-year question from JEE Main 2019, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.