JEE Main 2021 — Laws Of Motion Question with Solution
From: JEE Main 2021 (Online) 17th March Evening Shift
Question
A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is __________ N. (Round off to the Nearest Integer) [Take g = 10 ms-2 ]
This question includes a diagram. The text above accompanies the figure.
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Show full solutionCorrect answer: 30
Correct answer
30
Step-by-step explanation
f = T
N = T
(90 T) = T
0.5 (90 T) = T
90 T = 2T
3T = 90
T = 30 N
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This is a previous-year question from JEE Main 2021, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.