JEE Main 2025 — Magnetic Effects of Current Question with Solution
JEE Main 2025 (24 Jan Shift 1)
Question
A current of 5A exists in a square loop of side . Then the magnitude of the magnetic field at the centre of the square loop will be . where, value of p is _____ .
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Show full solutionCorrect answer: 8
Correct answer
8
Step-by-step explanation
Let B be the magnetic field due to single side $\begin{aligned} & \text { then } B=\frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{~d}}\left(\sin \theta_1+\sin \theta_2\right) \\ & =\frac{10^{-7} \times 5 \times 2}{\frac{1}{2 \sqrt{2}}} \times \frac{1}{\sqrt{2}}=2 \times 10^{-6} \\ & \therefore B_{\text {net }} \text { at centre } O=4 B \\ & =8 \times 10^{-6} \end{aligned}$
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