JEE Main 2019PhysicsMagnetic Effects of CurrentHardMCQ

JEE Main 2019Magnetic Effects of Current Question with Solution

JEE Main 2019 (08 Apr Shift 2)

Question

Two magnetic dipoles X and Y are placed at a separation d , with their axes perpendicular to each other. The dipole moment of Y is twice that of X . A particle of charge q is passing through their mid-point P , at angle θ=45o with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant? ( d is much larger than the dimension of the dipole)

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Show full solutionCorrect option: A
Correct answer
A0

Step-by-step explanation

BX=2μ04πMd/2 along x -axis
BY=μ04π2Md/2 along y -axis
BX=BY

Hence Bnet will be at 45o from x -axis.
Now, velocity and magnetic field are in same direction. Hence no force will act on the particle.

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About this question

This is a previous-year question from JEE Main 2019, covering the Magnetic Effects of Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.