JEE Main 2024PhysicsMagnetic Effects of CurrentEasyNumerical

JEE Main 2024Magnetic Effects of Current Question with Solution

JEE Main 2024 (27 Jan Shift 1)

Question

Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is 5.0 cm. The magnitude of the magnetic field at a point P midway between the wires is _____ μT. (Given: μ0=4π×10-7 T m A-1)

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Show full solutionCorrect answer: 160
Correct answer
160

Step-by-step explanation

The direction of the magnetic field at the observation point due to the current carrying conductor is determined by the right-hand cork screw rule.

From the given diagram, it is clear that as the conductors carry current in the mutually opposite direction, the direction of the magnetic fields produced by them at point P will be the same.

Hence, the required magnetic field at P due to the conductors can be calculated as follows:

B=2×μ0i2πa=2×4π×10-7×102π×52×10-2 T=160×10-6 T=160 μT

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About this question

This is a previous-year question from JEE Main 2024, covering the Magnetic Effects of Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.