JEE Main 2014PhysicsMathematics in PhysicsEasyMCQ

JEE Main 2014 — Mathematics in Physics Question with Solution

JEE Main 2014 (09 Apr Online)

Question

An experiment is performed to obtain the value of acceleration due to gravity g by using a simple pendulum of length L. In this experiment time for 100 oscillations is measured  by using a watch of 1 second least count and the value is 90.0 seconds. The length L is measured by using a meter scale of least count 1 mm and the value is 20.0 cm. The error in the determination of g would be :

Choose an option

Show full solutionCorrect option: D
Correct answer
D2.7%

Step-by-step explanation

T = 2 π L g

∴    T 2 = 4 π 2 L g

∴     g = 4 π 2 L T 2

% Error in g = Δ L L 0 × 1 0 0 + 2 Δ T T 0 × 1 0 0

                   = 1 × 1 0 - 3 0.20 × 1 0 0 + 2 1 9 0 × 1 0 0

                   = 0.5 + 2 1 0 9

                   = 0.5 + 2 0 9

                   = 0.5 + 2.22

                  = 2.7%

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Mathematics in Physics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2014, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.