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JEE Main 2021 — Mathematics in Physics Question with Solution

JEE Main 2021 (24 Feb Shift 2)

Question

The period of oscillation of a simple pendulum is T=2πLg. Measured value of L is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of 'g' will be:

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Show full solutionCorrect option: D
Correct answer
D1.13%

Step-by-step explanation

T=2πℓg

g=4π2ℓT2

Δgg=Δℓℓ+2ΔTT

Δgg=1×10-31+2×0.011.95

Δgg=0.0113 or 1.13%

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About this question

This is a previous-year question from JEE Main 2021, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.