JEE Main 2024 — Mathematics in Physics Question with Solution

Young's modulus is determined by the equation given by $\mathrm{Y}=49000\frac{\mathrm{m}}{\mathrm{l}}\frac{\mathrm{dyn}}{{\mathrm{cm}}^2}$ where $M$ is the mass and $l$ is the extension of wire used in the experiment. Now error in Young modules $(Y)$ is estimated by taking data from $M-l$ plot in graph paper. The smallest scale divisions are $5\mathrm{g}$ and $0.02\mathrm{cm}$ along load axis and extension axis respectively. If the value of $M$ and $l$ are $500\mathrm{g}$ and $2\mathrm{cm}$ respectively then percentage error of $Y$ is :