JEE Main 2014PhysicsMathematics in PhysicsMediumMCQ

JEE Main 2014 — Mathematics in Physics Question with Solution

JEE Main 2014 (06 Apr)

Question

The current voltage relation of diode is given by I = (e1000 V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.01 V  while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?

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Show full solutionCorrect option: A
Correct answer
A0.2 mA

Step-by-step explanation

I = e 1000 V / T - 1 mA

When I = 5 mA , e 1000 V / T = 6 mA

Also, dI = e 1000 V / T × 1000 T · dV

                = 6 mA × 1000 300 × 0.01

                = 0.2 mA  

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About this question

This is a previous-year question from JEE Main 2014, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.