JEE Main 2016PhysicsMathematics in PhysicsMediumMCQ

JEE Main 2016Mathematics in Physics Question with Solution

JEE Main 2016 (03 Apr)

Question

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

Choose an option

Show full solutionCorrect option: C
Correct answer
C92±2 s

Step-by-step explanation

T T s T i - T
  t 1  90  - 2
  t 2  91  - 1
  t 3  95  3
  t 4  92
  T i  92  Σ|Ti-T|N=1.5

Tr = 9 2 ± 1.5

Tr = 9 2 ± 2

Because least count of clock is 1s

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About this question

This is a previous-year question from JEE Main 2016, covering the Mathematics in Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.