JEE Main 2026 — Mechanical Properties of Fluids Question with Solution
JEE Main 2026 (05 April Shift 2)
Question
Eight mercury drops, each of radius , coalesce to form a bigger drop. The surface energy released in this process is _______. ( is the surface tension of mercury).
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Let the radius of the bigger drop be . Since the total volume remains conserved during the process:
Initial surface energy of the drops is:
Final surface energy of the bigger drop is:
The surface energy released in the process is:
Answer:
Initial surface energy of the drops is:
Final surface energy of the bigger drop is:
The surface energy released in the process is:
Answer:
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This is a previous-year question from JEE Main 2026, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.