JEE Main 2019PhysicsMechanical Properties of SolidsHardMCQ

JEE Main 2019Mechanical Properties of Solids Question with Solution

JEE Main 2019 (08 Apr Shift 1)

Question

A boy’s catapult is made of rubber cord which is 42 cm long, with 6 mm diameter of cross-section and of negligible mass. The boy keeps a stone weighing 0.02 kg on it and stretches the cord by 20 cm by applying a constant force. When released, the stone flies off with a velocity of 20 ms-1 . Neglect the change in the area of cross-section of the cord while stretched. The Young’s modulus of rubber is closest to:

Choose an option

Show full solutionCorrect option: A
Correct answer
A106N m-2

Step-by-step explanation

Elastic potential energy =12.Y. lL2AL
=12Y. 0.20.422.π×32×10-6×0.42
=1.35×10-6Y
Kinetic energy =12mv2=12×(0.02×202)
1.35×10-6 Y=4
Y=3×106 N m-2

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About this question

This is a previous-year question from JEE Main 2019, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.