JEE Main 2022PhysicsMechanical Properties of SolidsHardNumerical

JEE Main 2022 — Mechanical Properties of Solids Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

A string of area of cross-section 4 mm2 and length 0.5 is connected with a rigid body of mass 2 kg. The body is rotated in a vertical circular path of radius 0.5 m. The body acquires a speed of 5 m s-1 at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is _____ ×10-5. (Use Young's modulus 1011 N m-2 and g=10 m s-2)

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Show full solutionCorrect answer: 30
Correct answer
30

Step-by-step explanation

Given here, A=4 mm2, l=0.5 m, m=2 kg and vb=5 m s-1.

Tension at the bottom of the circular motion is given by T=mg+mvb2R

Using Young's modulus, we have 

Strain produced in the string when the body is at the bottom of the circle is ∆ll=TAY

=mg+mvb2lAY =20+2520.53×10-6×1011=30×10-5

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About this question

This is a previous-year question from JEE Main 2022, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.