JEE Main 2021PhysicsMechanical Properties of SolidsMediumNumerical

JEE Main 2021 — Mechanical Properties of Solids Question with Solution

JEE Main 2021 (27 Jul Shift 1)

Question

A stone of mass 20 g is projected from a rubber catapult of length 0.1 m and area of cross section 10-6 m2 stretched by an amount 0.04 m. The velocity of the projected stone is m s-1. (Young's modulus of rubber =0.5×109 N m-2)

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Show full solutionCorrect answer: 20
Correct answer
20

Step-by-step explanation

By energy conservation
12·YAL·x2=12mv2
0.5×109×10-6×(0.04)20.1=201000v2
∴ v2=400
v=20 m s-1

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About this question

This is a previous-year question from JEE Main 2021, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.