JEE Main 2024 — Mechanical Properties of Solids Question with Solution

One end of a metal wire is fixed to a ceiling and a load of $2 \mathrm{kg}$ hangs from the other end. A similar wire is attached to the bottom of the load and another load of $1 \mathrm{kg}$ hangs from this lower wire. Then the ratio of longitudinal strain of upper wire to that of the lower wire will be

[Area of cross section of wire $=0.005 {\mathrm{cm}}^2, Y=2\times {10}^{11} \mathrm{N} {\mathrm{m}}^{-2}$ and $g=10 \mathrm{m} {\mathrm{s}}^{-2}$]