JEE Main 2023PhysicsMechanical Properties of SolidsMediumMCQ

JEE Main 2023 — Mechanical Properties of Solids Question with Solution

JEE Main 2023 (30 Jan Shift 2)

Question

A force is applied to a steel wire A, rigidly clamped at one end. As a result elongation in the wire is 0.2 mm. If same force is applied to another steel wire B of double the length and a diameter 2.4 times that of the wire A, the elongation in the wire B will be (wires having uniform circular cross sections)

Choose an option

Show full solutionCorrect option: D
Correct answer
D6.9×10–2 mm

Step-by-step explanation

As we know, Y=FA∆ll

⇒F=YAl∆l

For both cases force applied is the same, therefore

YA∆ll1=YA∆ll2

⇒∆l2∆l1=A1A2×l2l1

⇒∆l20.2=πR2π2.4R2×21

⇒∆l2=6.9×10-2 mm

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About this question

This is a previous-year question from JEE Main 2023, covering the Mechanical Properties of Solids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.