JEE Main 2022PhysicsMotion In One DimensionEasyMCQ

JEE Main 2022 — Motion In One Dimension Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10 m in t s, the distance travelled by the toy in the next t s will be:

Choose an option

Show full solutionCorrect option: C
Correct answer
C30 m

Step-by-step explanation

Initial velocity of the particle is zero.

Applying equation of motion, we get 10=12×a×t2

Let distance covered in next t s is x.

Then, 10+x=12×a×2t2

⇒10+x=12at2×4  

⇒10+x=10×4

  ⇒x=30 m

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.