JEE Main 2023PhysicsMotion In One DimensionEasyMCQ

JEE Main 2023 — Motion In One Dimension Question with Solution

JEE Main 2023 (25 Jan Shift 2)

Question

The distance travelled by a particle is related to time t as x = 4t2. The velocity of the particle at t = 5 s is

Choose an option

Show full solutionCorrect option: A
Correct answer
A40 m s–1

Step-by-step explanation

Given here, x = 4t2

We know that velocity is the rate at which displacement changes with time. So, v=dxdt=d4t2dt=8t

Now, at t=5 s

Velocity of particle is v=8×5=40 m s-1.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.