JEE Main 2024PhysicsMotion In One DimensionEasyMCQ

JEE Main 2024 — Motion In One Dimension Question with Solution

JEE Main 2024 (31 Jan Shift 1)

Question

The relation between time ‘t’ and distance ‘x’ is t=αx2+βx, where α and β are constants. The relation between acceleration a and velocity v is:

Choose an option

Show full solutionCorrect option: A
Correct answer
Aa=-2αv3

Step-by-step explanation

Given: t=αx2+βx 

Differentiating w.r.t time, we get

dtdx=2αx+β

⇒1v=2αx+β

Differentiating w.r.t time again, we get

⇒-1v2dvdt=2αdxdt

⇒dvdt=-2αv3as v=dxdt⇒a=dvdt=-2αv3

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About this question

This is a previous-year question from JEE Main 2024, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.