JEE Main 2022PhysicsMotion In One DimensionMediumNumerical

JEE Main 2022 — Motion In One Dimension Question with Solution

JEE Main 2022 (24 Jun Shift 1)

Question

From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in _____ s.

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

When it is thrown upward, -h=v×6-12g62

When it is thrown downward, -h=-v×1.5-12g1.52

Therefore, 5h=536+9 h=45 m

When the ball is dropped, h=12gt2⇒45=12×10×t2⇒t=3 s

Alternate method, t=t1t2=6×1.5=3 s

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About this question

This is a previous-year question from JEE Main 2022, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.