JEE Main 2023PhysicsMotion In One DimensionEasyMCQ

JEE Main 2023 — Motion In One Dimension Question with Solution

JEE Main 2023 (06 Apr Shift 2)

Question

A particle starts with an initial velocity of 10.0 ms-1 along x-direction and accelerates uniformly at the rate of 2.0 m s-2. The time taken by the particle to reach the velocity of 60.0 m s-1 is _____.

Choose an option

Show full solutionCorrect option: A
Correct answer
A25 s

Step-by-step explanation

The given data is 

v=60 m s-1u=10 m s-1a=2 m s-2

Using the equation v=u+at, we get

60=10+2t⇒t=60-102⇒t=25 s

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.