JEE Main 2020PhysicsMotion In One DimensionEasyMCQ

JEE Main 2020 — Motion In One Dimension Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

A particle of mass m and charge q is released from rest in a uniform electric field. If there is no other force on the particle, the dependence of its speed v on the distance x travelled by it is correctly given by (graphs are schematic and not drawn to scale)

Choose an option

Show full solutionCorrect option: B
Correct answer
B

Step-by-step explanation

The particle is at rest initially.

So, the initial velocity u=0 m s-1.

The force on the charged particle in the uniform electric field,

F=qE

⇒ ma=qE

⇒ a=qEm

Applying the velocity-displacement equation under constant acceleration,

v2=u2+2ax

⇒ v2=02+2qEmx

⇒ v2=2qEmx

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About this question

This is a previous-year question from JEE Main 2020, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.