JEE Main 2021PhysicsMotion In One DimensionHardMCQ

JEE Main 2021 — Motion In One Dimension Question with Solution

JEE Main 2021 (27 Aug Shift 2)

Question

Water drops are falling from a nozzle of a shower onto the floor from a height of 9.8 m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.

Choose an option

Show full solutionCorrect option: D
Correct answer
D7.35 m

Step-by-step explanation

For first drop.

h=12g(2n)2

For 2nd  drop

h'=12g(n)2

hh'=41

h'=h4=9.84

so height of 2nd  drop

H=h-h'=9.8-9.84=34×9.8=7.35 m

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About this question

This is a previous-year question from JEE Main 2021, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.